maximum number of iterations 2147483647 exceeded

Hi, First of all many thanks for this great library ! You rock guys !

Well, I started testing your trial version and got this thing:

<br />
    @Test<br />
    public void testSuanshuStat() throws Exception {<br />
        double aLevel = 0.05;<br />
        int N = 500;<br />
<br />
        // normal distr with m=100, sigma=1<br />
        NormalRng ng = new NormalRng(100, 1);<br />
<br />
        // generate N numbers<br />
        double[] vNorm = new double[N];<br />
        for (int i = 0; i < N; i++)<br />
            vNorm<i> = ng.nextDouble();<br />
<br />
        for (int i = 0; i < 200; i++) {<br />
            T t = new T(vNorm, 100);<br />
            double[] rr = t.confidenceInterval(0.975);<br />
            System.out.println(i + "> T = " + t.pValue() + " l = " + rr[0] + " r = " + rr[1]);<br />
        }<br />
    }<br />
</i>

After I ran this code I got next output:

<br />
0> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
1> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
2> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
3> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
4> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
5> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
6> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
7> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
8> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
9> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
10> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
11> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
12> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
13> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
14> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
15> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
16> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
17> T = 0.7016288954439946 l = 99.90095700580275 r = 100.0667037706929<br />
<br />
com.numericalmethod.suanshu.analysis.function.rn2r1.ContinuedFraction$MaxIterationsExceededException: maximum number of iterations 2147483647 exceeded<br />
at com.numericalmethod.suanshu.analysis.function.rn2r1.ContinuedFraction.evaluate(do:156)<br />
at com.numericalmethod.suanshu.analysis.function.rn2r1.ContinuedFraction.evaluate(do:257)<br />
at com.numericalmethod.suanshu.analysis.function.special.BetaRegularized.evaluate(uq:130)<br />
at com.numericalmethod.suanshu.analysis.function.special.BetaRegularized.evaluate(uq:82)<br />
at com.numericalmethod.suanshu.analysis.function.special.BetaRegularizedInverse$1.evaluate(dv:259)<br />
at com.numericalmethod.suanshu.analysis.uniroot.Halley.solve(qr:231)<br />
at com.numericalmethod.suanshu.analysis.uniroot.Uniroot.solve(np:116)<br />
at com.numericalmethod.suanshu.analysis.function.special.BetaRegularizedInverse.evaluate(dv:15)<br />
at com.numericalmethod.suanshu.stats.distribution.univariate.TDistribution.quantile(mi:45)<br />
at com.numericalmethod.suanshu.stats.test.mean.T.confidenceInterval(cl:12)<br />
<br />

Number (i) when I can get this exception depends on number of data in series. For N=1000 I get that at i==5 etc. Seems it uses some interior static buffers and doesn’t free it. Could you advise me how to refresh this buffer or how to avoid this situation ?